What is the amount of a 50% active ingredient pesticide formulation required to create a 3-gallon mixture at 2% dilution?

To determine the amount of a 50% active ingredient pesticide formulation needed to create a 3-gallon mixture at a 2% dilution, we first need to calculate the total volume of the active ingredient required.

A 2% dilution means that there are 2 ounces of active ingredient in every 100 ounces of the mixture. To find out how many ounces are in 3 gallons, we can convert gallons to ounces since there are 128 ounces in a gallon:

3 gallons x 128 ounces/gallon = 384 ounces.

Next, we calculate 2% of the total mixture:

0.02 x 384 ounces = 7.68 ounces.

Since the pesticide formulation is 50% active ingredient, we need to find the volume of the formulation that contains 7.68 ounces of active ingredient. To do this, we divide the amount of active ingredient needed by the percentage of active ingredient in the formulation:

7.68 ounces ÷ 0.50 = 15.36 ounces.

Therefore, to create a 3-gallon mixture at a 2% dilution using a 50% active ingredient pesticide formulation, you will require 15.36 ounces of the formulation.